The Red dragon who is 8 ft tall walks away from a 20 ft lampost at a speed of 2 ft/s. Find the rate at ehich his shadow is increasing in length.
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A rate is defined as distance divided by time. The height has nothing to do with solving the problem.
The speed is the same thing as a RATE, because it is distance divided by time or 2 feet per second.
Find the rate the shadow is increasing. Well, trick question here...the RATE is 2 ft/s whether it is 20 ft to the lampost or 100 feet the lampost. As long as the rate is CONSTANT, then the rate is the same. As he moves towards the lampost, the shadow becomes bigger and bigger but so long as the rate is >>CONSTANT<< it does not change - it remains 2 ft/s
The speed is the same thing as a RATE, because it is distance divided by time or 2 feet per second.
Find the rate the shadow is increasing. Well, trick question here...the RATE is 2 ft/s whether it is 20 ft to the lampost or 100 feet the lampost. As long as the rate is CONSTANT, then the rate is the same. As he moves towards the lampost, the shadow becomes bigger and bigger but so long as the rate is >>CONSTANT<< it does not change - it remains 2 ft/s