Remove grouping symbols and simplify

1. 2x-{3y-[5x-(7y-6x)]}
2. 8x+[(3x-2y)+(6x-9)-(x+y)]
3. (2x-3y)+(y-4z)-(2-3x)
4.[2s-3(s-2r)]+[4(s+r)-8s]
5. 3y-[2y+3x-(2x-3y)]+4x
please show d solution.thank u

1. 2x-{3y-[5x-(7y-6x)]}

2x - { 3y - [ 5x - ( 7y - 6x ) ] }
= 2x - [ 3y - ( 5x - 7y + 6x ) ]
= 2x - [ 3y - ( 6x + 5x - 7y ) ]
= 2x - [ 3y - ( 11x - 7y ) ]
= 2x - ( 3y - 11x + 7y )
= 2x - ( - 11x + 7y + 3y )
= 2x - ( - 11x + 10y )
= 2x + 11x - 10y
= 11x + 2x - 10y
= 13x - 10y

2. 8x+[(3x-2y)+(6x-9)-(x+y)]

8x + [ ( 3x - 2y ) + ( 6x - 9 ) - ( x + y ) ]
= 8x + ( 3x - 2y + 6x - 9 - x - y )
= 8x + ( 6x + 3x - x - 2y - y - 9 )
= 8x + ( 9x - x - 3y - 9 )
= 8x + ( 8x - 3y - 9 )
= 8x + 8x - 3y - 9
= 16x - 3y - 9

3. (2x-3y)+(y-4z)-(2-3x)

( 2x - 3y ) + ( y - 4z ) - ( 2 - 3x )
= 2x - 3y + y - 4z - 2 + 3x
= 3x + 2x - 3y + y - 4z - 2
= 5x - 2y - 4z - 2

4.[2s-3(s-2r)]+[4(s+r)-8s]

[ 2s - 3 ( s - 2r ) ] + [ 4 ( s + r ) - 8s ]
= ( 2s - 3s + 6r ) + [ ( 4s + 4r ) - 8s ]
= ( - 3s + 2s + 6r ) + ( 4s + 4r - 8s )
= ( - s + 6r ) + ( - 8s + 4s + 4r )
= - s + 6r + ( - 4s + 4r )
= - s + 6r - 4s + 4r
= - 4s - s + 6r + 4r
= - 5s + 10r
= - 5 ( s - 2r )

5. 3y-[2y+3x-(2x-3y)]+4x

3y - [ 2y + 3x - ( 2x - 3y ) ] + 4x
= 3y - ( 2y + 3x - 2x + 3y ) + 4x
= 3y - ( 3x - 2x + 3y + 2y ) + 4x
= 3y - ( x + 5y ) + 4x
= 3y - x - 5y + 4x
= 4x - x - 5y + 3y
= 3x - 2y

To get the answer use the PEMDAS method parenthasis exponents multiplication divisob addition subtraction then combine and like symbols such as Iu had 8x (3x(5x+4x) it would be first take 3x times 5x to get 15 x squared and also take 3x times 4x to get 18x sguared now add the 15xssguared and the 18x squared to get 33x squared then u would times that all by 8x.