Hi I am trying to review ahead before semester starts and this problem is confusing me it's a graph so I am attaching the link it's problem #28. The college is closed so I cannot get help from any professor.
http://www.baruch.cuny.edu/sacc/documents/2205AdditionalProblemsfortheFEM.pdf
http://www.baruch.cuny.edu/sacc/documents/2205AdditionalProblemsfortheFEM.pdf
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I think A. A is 1, B is negative, I think C is a goofy answer thats not right, D is same as A, and E is the avg of the two slopes which is also neg.
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a)f(0) = 1
d) is -1
e) is 0
c) we get lim h -> 0 (f'(h)-1)/h is a lim 0/0 but with L'hospitals rule = lim h->0 f'(h) = f'(0)
b) Draw a line from (1,0) to (-1,2) the slope = -1 is less than f'(0) cant' be it
answer is a f(0)
d) is -1
e) is 0
c) we get lim h -> 0 (f'(h)-1)/h is a lim 0/0 but with L'hospitals rule = lim h->0 f'(h) = f'(0)
b) Draw a line from (1,0) to (-1,2) the slope = -1 is less than f'(0) cant' be it
answer is a f(0)