How do you verify the identity: 2sin^2 2t + cos 4t=1

[From: ] [author: ] [Date: 12-07-01] [Hit: ]

Please Help wth this calculus problem!!

Let Θ = 2t
2sin^2 2t + cos 4t
= 2sin²Θ + cos(2Θ)
= 2sin²Θ + (cos²Θ - sin²Θ
= sin²Θ+cos²Θ
= 1
QED

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