f(x) = sqrt(1 - 2x).
Somehow the answer is f'(x) = -[1/sqrt(1-2x)].
Please help.
Somehow the answer is f'(x) = -[1/sqrt(1-2x)].
Please help.
-
y = √(1 - 2x)
dy/dx = [ 1/ 2√(2 - x) ]* (-2)
= - 1 / √(2 - x)
dy/dx = [ 1/ 2√(2 - x) ]* (-2)
= - 1 / √(2 - x)
-
f(x) = √(1 - 2x)
f '(x) = 1/(2√(1 - 2x)) * -2 = -1/√(1 - 2x))
f '(x) = 1/(2√(1 - 2x)) * -2 = -1/√(1 - 2x))