Do I make this into a limit and use natural logs? Or am I way off base? Please show steps!
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Σ (4/5)^k - Σ (3/5)^k
The first is a geometric series with common ratio r=4/5 and first term 1
sum of series 1 = a/(1-r) = 1/(1-4/5) = 5
sum of the second series = 1/(1-3/5) = 5/2
5-5/2 = 5/2
Sum = 2.5
The first is a geometric series with common ratio r=4/5 and first term 1
sum of series 1 = a/(1-r) = 1/(1-4/5) = 5
sum of the second series = 1/(1-3/5) = 5/2
5-5/2 = 5/2
Sum = 2.5