F(x)=x2^ and g(x)=2x-3.if f(x)+g(x)=3.what is the value for x.

x^2+2x-3=3

x^2+2x-6=0

(x-?)(x-?)=0

this is not solveable because you need two multibles of 6, one pos the other neg, to be able to add together to 2, and multiply together to -6. this is not possible.