Identify the center and radius length of the circle whose equation is: (x-4)^2 + (y+3)^2 = 25
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Identify the center and radius length of the circle whose equation is: (x-4)^2 + (y+3)^2 = 25

[From: ] [author: ] [Date: 12-05-28] [Hit: ]
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Identify the center and radius length of the circle whose equation is: (x-4)^2 + (y+3)^2 = 25 ?

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Center: 4, -3

radius= 5

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(x-h)^2+(y-k)^2=r^2 (standard equation of a circle)

r= radius
center of circle (h,k)

r=sqrt(25)
r=5

h=4
k=-3 [(y--k)=(y+k)]

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(x - 4)^2 + (y + 3)^2 = 25

Center: (4, -3)

Radius = √25 = 5
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