The function f is defined as y=f(x)= (2x+1)/(x-3), where x does not equal 3. Find the value k so that f^-1 (x) = (3x+1)/(x-k)
a) 0
b) 1
c)2
d)-1
e) -2
I don't understand what the question is asking for (what the second sentence has to do with the first, what the inverse equation is referring to). So any help on that and/or the steps for getting the answer would be much, much appreciated. Thanks!
a) 0
b) 1
c)2
d)-1
e) -2
I don't understand what the question is asking for (what the second sentence has to do with the first, what the inverse equation is referring to). So any help on that and/or the steps for getting the answer would be much, much appreciated. Thanks!
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y = (2x + 1)/(x - 3)
yx - 3y = 2x + 1
yx - 2x = 3y + 1
x = (3y + 1)/(y - 2)
y = (3x + 1)/(x - 2) = f^-1(x)
k = 2
yx - 3y = 2x + 1
yx - 2x = 3y + 1
x = (3y + 1)/(y - 2)
y = (3x + 1)/(x - 2) = f^-1(x)
k = 2
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To get the inverse switch x and y and solve for y.
x = (2y+1)/(y-3)
xy-3x = 2y+1
y(x-2) = (3x+1)
y = (3x+1)/(x-2)
k=2
Answer c)
x = (2y+1)/(y-3)
xy-3x = 2y+1
y(x-2) = (3x+1)
y = (3x+1)/(x-2)
k=2
Answer c)
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y = (2*x + 1)/(x - 3)
x = (2*y + 1)/(y - 3)
x*y - 3*x = 2*y + 1
x*y - 2*y = 3*x + 1
y*(x - 2) = 3*x + 1
f^-1(x) = y = (3*x + 1)/(x - 2), so k = 2, c
x = (2*y + 1)/(y - 3)
x*y - 3*x = 2*y + 1
x*y - 2*y = 3*x + 1
y*(x - 2) = 3*x + 1
f^-1(x) = y = (3*x + 1)/(x - 2), so k = 2, c
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hmm