What is the vertex of y = -3x^2 -12x -2

Dumb question, I just blanked out...

y = -3x^2 - 12x - 2

y = -3(x^2 + 4x + 2/3)

y = -3((x + 2)^2 - 10/3)

y = -3(x + 2)^2 + 10

Vertex is (-2, 10)

Review how to convert to the vetex form of the quadratic equation. Lots of help with google there.

Anyway that is what you can do, other than graphing it on a graphing calculator


Do this:

-3x^2 -12x - 2
-3x^2 - 12x = 2

-3(x^2 + 4) = 2

-3(x^2 +4x + 4) = 2 - 12

-3(x + 2)^2 = -10

-3x(x + 2)^2 + 10 = 0

The vertex is -2,10