Math 12 Identities help please

Math 12 Identities help please?
Hey, need a little help with this identity, can't seem to solve it...

Prove that the left side = right side
6c.) (sin + tan)/(cos + 1) = tan

Any help appreciated! Thanks so much!

(sinx+tanx) / (cosx+1) = tanx
(sinx+(sinx/cosx)) / (cosx+1) = tanx
((sinxcosx/cosx)+(sinx/cosx)) / (cosx+1) = tanx
((sinxcosx+sinx)/cosx) / (cosx+1) = tanx
((sinxcosx+sinx)/cosx) / ((cosx+1)/1) = tanx
((sinxcosx+sinx)/cosx) * (1/(cosx+1)) = tanx
(sinx(cosx+1)/cosx) * (1/(cosx+1)) = tanx
sinx(cosx+1)(1) / (cosx(cosx+1)) = tanx
sinx / cosx = tanx
tanx = tanx

EDIT: When you prove trigonometric identities, you are supposed to leave one side alone and only work on the other side until it is identical to that one. In this problem, it makes much more sense to leave the tanx side alone and work on only the left side. You are not supposed to do anything to both sides. That's not how a proof like this is done.

sin + tan = cos(sin/cos) + tan = costan + tan = tan(cos + 1)
Divide both sides by (cos + 1).
(sin + tan)/(cos + 1) = tan . . . provided cos ≠ -1

sin + tan = tan cos + tan

sin + tan = (sin/cos * cos) + tan = sin + tan