I dont understand how to factor with two different variables like this
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factor using rule for difference of two squares
x^2 - y^2 = (x + y)(x - y)
a^2 - 36b^2
= (a)^2 - (6b)^2
= (a + 6b)(a - 6b)
x^2 - y^2 = (x + y)(x - y)
a^2 - 36b^2
= (a)^2 - (6b)^2
= (a + 6b)(a - 6b)
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a^2 - 36b^2
=(a-6b)(a+6b)
When u have a function/ expression in the form of (x^2)-(y^2), you can always factorise it to (x-y)(x+y).
(a^2)-36(b^2) is the expression so (x^2)=(a^2) and (y^2)=36(b^2).
x=a or -a and y=-6b or 6b.
Therefore (a^2)-36(b^2)=(a-6b)(a+6b), (-a-6b)(-a+6b). The second answer is -1 multipied by the first answer. So you can write (a-6b)(a+6b)=(a^2)+6ba-6ba-36(b^2)=(a^2)…
=(a-6b)(a+6b)
When u have a function/ expression in the form of (x^2)-(y^2), you can always factorise it to (x-y)(x+y).
(a^2)-36(b^2) is the expression so (x^2)=(a^2) and (y^2)=36(b^2).
x=a or -a and y=-6b or 6b.
Therefore (a^2)-36(b^2)=(a-6b)(a+6b), (-a-6b)(-a+6b). The second answer is -1 multipied by the first answer. So you can write (a-6b)(a+6b)=(a^2)+6ba-6ba-36(b^2)=(a^2)…
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a² - 36b² this is what we call the difference of two squares
(a +6b)(a -6b) as simple as that
ask your self:
what by what gives a²
what by what gives b²
what what sign but what sign gives a minus +* -
(a +6b)(a -6b) as simple as that
ask your self:
what by what gives a²
what by what gives b²
what what sign but what sign gives a minus +* -
-
a^2 - 36b^2
= (a + 6b)(a - 6b)
= (a + 6b)(a - 6b)