Math Help..surface area and volume

I need the volume and surface area of these, PLEASE!
cube - l= 2in w=2in h=2in
cube l=1in w=1in h=1in
square prism l=7in w=4in h=11
rectangular prism l=5in w=4in h=3in
square pyramid l=8in w=8in h=10 in

PLEASE HELP me by the way, l= length w=width h=height

Find the volume and surface area of the
given solids:
1).
Cube -
l = 2 in, w =2 in, and h = 2 in
V = 8 cubic inches
SA = 24 square inches

2).
Cube -
l =1 in, w = 1 in, and h = 1 in
V = 1 cubic inch
SA = 6 square inches

3).
Prism -
l = 7 in, w = 4 in, and h = 11 in
V = 308 in^3
Surface Area of Prism:
[ 2(lw) + (2l + 2w)h ]
= 56 + 22*11
= 298 square inches

4).
Rectangular prism -
l = 5 in, w = 4 in, and h = 3 in
V = 60 in^3
SA (Cuboid):
[ 2(lw) + (2l + 2w)h ]
= 40 + 18*3
= 94 square inches

5).
Pyramid
Volume =1/3 x area of base x height
Surface Area of Any Pyramid
= area of base + area of each of the lateral faces
Regular pyramid = area of base + 1/2 ps
where p = perimeter of the base, s = slant height
Square pyramid = b^2 + 2bs
where b = length of the base, s = slant height
Square pyramid -
l = 8 in, w = 8 in, and h = 10 in
s = sqrt (164)
V = 213 1/3 in^3
SA
= 64 + 16*(164)^(1/2)
= 268.89997559785115 in^2

Cube with l=2
volume(v)=l^3
v=2^3=8 in^3
surface area(S.A)=6l^2
S.A=6*2^2=24 in^2

cube with l=1
v=1^3=1 in^3
S.A=6*1^2=6 in^2

question 3 is not correct because a square prism is supposed to have a square base. So thats a rectangular prism.

Q4. Volume of a prism(v)=base area(A)*height(h)
A=l*b
A=5*4=20 in^2
h=3
v=A*h
v=20*3=60 in^3

surface area of a rectangular prism=area of a cuboid=2(lb+bh+lh)
2(5*4+4*3+5*3)
2(20+12+15)
2(47)=94 in^2

volume of a pyramid(v)=1/3*base area(A)*h