(-4,5) = sqrt 41
I don't understand how they got sqrt 41.
I don't understand how they got sqrt 41.
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h^2 = (-4)^2+5^2 = 16+25 = 41
h = sqrt(41)
h = sqrt(41)
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Are you asking to find the distance from the origin to the point (-4,5) using the Pythagorean Theorem, and if the answer is 41?
a^2+b^2 = c^2
(5)^2+(4)^2 = c^2
25+16 = c^2
41 = c^2
√41 = √c^2
√41 = c
a^2+b^2 = c^2
(5)^2+(4)^2 = c^2
25+16 = c^2
41 = c^2
√41 = √c^2
√41 = c
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a^2+b^2=c^2
a=-4
b=5
So a^2 is 16 and b^2 is 25. Add them together to get 41. That's c^2. So you take the square root to get c, which is the length of the hypotenuse. Since there's no even square of 41, the final answer is sqrt(41).
a=-4
b=5
So a^2 is 16 and b^2 is 25. Add them together to get 41. That's c^2. So you take the square root to get c, which is the length of the hypotenuse. Since there's no even square of 41, the final answer is sqrt(41).
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4^2 + 5^2 = c^2
16 + 25 = c^2
41 = c^2
I hope this information was very helpful.
16 + 25 = c^2
41 = c^2
I hope this information was very helpful.
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(-4)^2 + (5)^2 = c^2
16 + 25 = c^2
41 = c^2
sqrt(41) = sqrt(c^2)
c = sqrt(41)
16 + 25 = c^2
41 = c^2
sqrt(41) = sqrt(c^2)
c = sqrt(41)
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(-4)^2+5^2=c^2
16+25=c^2
41=c^2
c=sqrt41
16+25=c^2
41=c^2
c=sqrt41