What is the equation in point-slope form of the line passing through (0, 5) and (–2, 11)?
y – 5 = –3(x + 2)
y – 5 = 3(x + 2)
y – 11 = –3(x – 2)
y – 11 = –3(x + 2)
Could you help me solve this multiple choice question? I think its the first or second choice but I'm not sure. Thanks in advance to anyone who answers, I really appreciate it (:
y – 5 = –3(x + 2)
y – 5 = 3(x + 2)
y – 11 = –3(x – 2)
y – 11 = –3(x + 2)
Could you help me solve this multiple choice question? I think its the first or second choice but I'm not sure. Thanks in advance to anyone who answers, I really appreciate it (:
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It's the last one.
Find the slope first:
(y2-y1)/(x2-x1)
(11-5)/(-2-0)
6/-2
m=-3
Now plug into the point-slope formula
y -y1 = m(x-x1) or y-y2 = m(x-x2)
y-11 = -3(x+2)
Find the slope first:
(y2-y1)/(x2-x1)
(11-5)/(-2-0)
6/-2
m=-3
Now plug into the point-slope formula
y -y1 = m(x-x1) or y-y2 = m(x-x2)
y-11 = -3(x+2)
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y - 11 = [(11-5)/(-2-0)] * (x + 2)
y - 11 = [6/(-2)] (x + 2)
y - 11 = -3(x + 2)
y - 11 = [6/(-2)] (x + 2)
y - 11 = -3(x + 2)