What is the equation of the line passing through (2, –2) and perpendicular to the line y = –x + 3 in slope-int

What is the equation of the line passing through (2, –2) and perpendicular to the line y = –x + 3 in slope-intercept form?

y = x

y = –x

y = x – 4

y = x + 4

Could you help me solve this multiple choice question? I think its the first or second choice but I'm not sure. Thanks in advance to anyone who answers, I really appreciate it (:

Clearly it can't be "y=x" like the other comment says, because that would mean the point would be (2, 2), and it's obviously not.

The correct way to do it is as follows:

You know the line you want to find is perpendicular to y=-x+3, which means it will have the same slope of (-1)

So, plug this slope and the given point into your slope-intercept formula and find the y-intercept (which is "b"):

y = mx + b
y = -x + b
-2 = -2 + b
0 = b

Thus the equation for this line is:

y = -x + 0
or
y = -x

Ok,let's figure out the gradient first: the gradient of y= -x +3 is -1 (its in mx + c form). A line perpendicular to that would have a gradient of one. Then we can use point-gradient formula:

y-y1 = m(x-x1)
y - -2 = x - 2
y = x - 4

So its the third option.

If you draw it, a line with a slope of 1 passing through (2, -2) is going to meet the y axis at -4, so this makes sense.

Gradient means the slope, by the way.

y=x
like a boss