w2(the 2 is squaring the w) + 7w + 4 = 0
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I believe you are trying to solve the quadratic equation, not multiply two binomials. And since "FOIL" is a crutch to allow the rote multiplication of two binomials without requiring any understanding of the process, "FOIL" is not applicable to the problem presented.
w² + 7w + 4 = 0
w² + 7w = -4
w² + 7w + 49/4 = 49/4 - 16/4 = 33/4
(w + 7/2)² = 33/4
w + 7/2 = ±√33/2
w = (-7±√33)/2
w² + 7w + 4 = 0
w² + 7w = -4
w² + 7w + 49/4 = 49/4 - 16/4 = 33/4
(w + 7/2)² = 33/4
w + 7/2 = ±√33/2
w = (-7±√33)/2
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w2 + 7w + 4 = 0
We cannot use FOIL in this math problem.
FOIL is multiplying the terms, NOT adding the terms ..
In foil, there should be terms like,
F - First terms
0 - Outer term or extremes
I - Inner terms or means and
L -Last terms or second terms
And also, the equation " w2 + 7w + 4 = 0 " cannot be factored..
Therefore, there is no solution to the problem.
We cannot use FOIL in this math problem.
FOIL is multiplying the terms, NOT adding the terms ..
In foil, there should be terms like,
F - First terms
0 - Outer term or extremes
I - Inner terms or means and
L -Last terms or second terms
And also, the equation " w2 + 7w + 4 = 0 " cannot be factored..
Therefore, there is no solution to the problem.