Stoichiometry Question please help asap! :)
Favorites|Homepage
Subscriptions | sitemap
HOME > > Stoichiometry Question please help asap! :)

Stoichiometry Question please help asap! :)

[From: ] [author: ] [Date: 12-05-14] [Hit: ]
and CO that will be in the reaction vessel once the reactants have reacted as much as possible.10g TiO2 / 79.9g/mole = 0.10g C / 12g/mole = 0.0.125moles TiO2 x (2C / 1TiO2) = 0.......
Consider the reaction between TiO2 and C:
TiO2(s) + 2 C(s) ------> Ti(s) + 2 CO(g)

A reaction vessel initially contains 10.0 g of each of the reactants. Calculate the masses of TiO2, C, Ti, and CO that will be in the reaction vessel once the reactants have reacted as much as possible. (assume 100% yield)

-
TiO2 + 2C --> Ti + 2CO

10g TiO2 / 79.9g/mole = 0.125moles
10g C / 12g/mole = 0.83moles

0.125moles TiO2 x (2C / 1TiO2) = 0.25moles C required
TiO2 = limiting reactant
TiO2 is gone
0.25moles C are used from the 0.83moles present, leaving 0.58molesC or 7g C
0.125moles TiO2 yields 0.125moles T = 6g
0.125moles TiO2 yields 0.25moles CO = 7g
1
keywords: please,help,asap,Question,Stoichiometry,Stoichiometry Question please help asap! :)
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .