Solve the equation and explain how you do it

xsquared+7x+12=0

and explain how to do it pleaseee

x^2 + 7x + 12 = 0
(x + 4)(x + 3) = 0
x = -4 and x = -3

You must find two numbers that will add to get the coefficient in front of the x variable and that will multiply together to get the constant number in the quadratic equation.

Cheers!

xsquared+7x+12=0

Translate.

x^2 + 7x + 12 = 0

Perform the FOIL method.

(x + 4)(x + 3) = 0

Set each group equal to zero. Solve for x.

x + 4 = 0

Subtract 4 to both sides of the equal sign.

x + 4 - 4 = 0 - 4

x = - 4

x + 3 = 0

Subtract 3 to both sides of the equal sign.

x + 3 - 3 = 0 - 3

x = - 3

The answers are x = - 3 or - 4

(x+a)(x+b) = x^2 +ax+bx+ab= x^2 +(a+b)x + ab
so your equation needs two numbers 'a' and 'b' which will add to give 7 and multiply to give 12

2 such numbers are 3 and 4

therefore your equation simplifies to (x+3)(x+4)=0
and hence x=-3 or x=-4

FYI, xsquared = x^2

Quadratic Equations are in the form ax^2 + bx + c = 0

http://en.wikipedia.org/wiki/Completing_…

x^2+7x+12=0
(x+4)(x+3)=0
x=-3, x=-4

Learn factoring bud!

No. Learn your quadratics.