This has something to do with logs and natural logs and all that jazz... please provide a detailed step by step solution :D
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(1/3)e^x + 1 = 5
(e^x/3) + 1 = 5
e^x = 12
x = log 12
x = 2 log (2) + log (3)
x = 2.484906649788
(e^x/3) + 1 = 5
e^x = 12
x = log 12
x = 2 log (2) + log (3)
x = 2.484906649788
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(1/3) * e^(x) + 1 = 5
(1/3) * e^(x) = 4
e^(x) = 12
x = ln(12)
or
(1/3) * e^(x + 1) = 5
e^(x + 1) = 15
x + 1 = ln(15)
x = ln(15) - 1
(1/3) * e^(x) = 4
e^(x) = 12
x = ln(12)
or
(1/3) * e^(x + 1) = 5
e^(x + 1) = 15
x + 1 = ln(15)
x = ln(15) - 1