f(x) = 4 radical x+ 3 cos x
Please help this stuff is really giving me a hard time!!
Please help this stuff is really giving me a hard time!!
-
Taking the anti-derivative would mean taking the indefinite integral of the function.
f(x) = 4√x + 3cosx
You would first integrate the 4√x , which can also be written as 4x^½ . This integrates to (8/3)x^3/2.
Then you would integrate the 3cosx, which integrates to 3sinx.
Then you would add a constant, C.
So the final answer would be:
∫ f(x) = (8/3)x^3/2 + 3sinx + C.
If you need more help, type in your equation (or almost anything else really) into the search bar of http://www.wolframalpha.com/ - it comes up with the solution with explanations and graphs and all that good stuff :)
f(x) = 4√x + 3cosx
You would first integrate the 4√x , which can also be written as 4x^½ . This integrates to (8/3)x^3/2.
Then you would integrate the 3cosx, which integrates to 3sinx.
Then you would add a constant, C.
So the final answer would be:
∫ f(x) = (8/3)x^3/2 + 3sinx + C.
If you need more help, type in your equation (or almost anything else really) into the search bar of http://www.wolframalpha.com/ - it comes up with the solution with explanations and graphs and all that good stuff :)