dy/dt = (t^3) * t
where ( * ) = convolution
for y(0) = 6
and
t ≥ 0
*****Thanks you for all of your help!! I really appreciate it!!!*****
where ( * ) = convolution
for y(0) = 6
and
t ≥ 0
*****Thanks you for all of your help!! I really appreciate it!!!*****
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Note that L{t^3 * t}
= L{t^3} · L{t}
= (3!/s^4) · (1/s^2)
= 6/s^6.
So, applying L to both sides of the DE yields
s Y(s) - y(0) = 6/s^6.
==> s Y(s) - 6 = 6/s^6.
Solve for Y(s):
Y(s) = 6/s + 6/s^7.
Inverting term yields
y(t) = 6 + (1/6!) t^6 = 6 + (1/720) t^6.
I hope this helps!
= L{t^3} · L{t}
= (3!/s^4) · (1/s^2)
= 6/s^6.
So, applying L to both sides of the DE yields
s Y(s) - y(0) = 6/s^6.
==> s Y(s) - 6 = 6/s^6.
Solve for Y(s):
Y(s) = 6/s + 6/s^7.
Inverting term yields
y(t) = 6 + (1/6!) t^6 = 6 + (1/720) t^6.
I hope this helps!