Given the following rational function !

[From: ] [author: ] [Date: 12-04-21] [Hit: ]

if any-I assume this is f(x)=y =(x^2-5x-6)/(x+11) = x-16 + 182/(x+11) by division.A) There is no horizontal asymptote since y approaches y=x-16 as x increases.For a horizontal asymptote y must approach a constant.B) A vertical asymptote is where the bottom of the fraction =0, x=-11.C) Oblique is y=x-16 following A.......

please Help me and show step by step so i can understand it.
it say given the following rational function
Find :
f(x)=x^2-5x-6/x+11
A) the horizontal asymptote(s)
b) the vertical asymptote(s), if any
c) the oblique asymptote(s), if any

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I assume this is f(x)=y =(x^2-5x-6)/(x+11) = x-16 + 182/(x+11) by division.
A) There is no horizontal asymptote since y approaches y=x-16 as x increases.
For a horizontal asymptote y must approach a constant.
B) A vertical asymptote is where the bottom of the fraction =0, x=-11.
C) Oblique is y=x-16 following A.

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