Trig help! Finding the degree measure of each angle
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Trig help! Finding the degree measure of each angle

[From: ] [author: ] [Date: 12-04-14] [Hit: ]
B, and C for the lengths of the sides (C is the Hypotenuse).B = sqrt (13^2 - 3^2) = 12.Angle opposite to A = asin (3/13) = 13.Angle opposite to B = acos (3/13) = 76.658 deg-The cosine of the angle between the leg and the hypotenuse is 3/13,......
The hypotenuse of a right triangle is 13 inches. If one leg is 3 inches, find the degree measure of each angle.

The angle opposite the 3-inch leg is ?

The other acute angle of the right triangle is ?

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Use A, B, and C for the lengths of the sides (C is the Hypotenuse).
C = 13
A = 3
B = sqrt (13^2 - 3^2) = 12.649
Angle opposite to A = asin (3/13) = 13.342 deg
Angle opposite to B = acos (3/13) = 76.658 deg

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The cosine of the angle between the leg and the hypotenuse is 3/13, so the angle is 76.66°
The other angle then would be 13.34°, because the acute angles of a right triangle are complementary

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Let A be the angle opposite the leg of 3 in, and B be the other acute angle.

sin A = 3/13 = 13.3423638... ≈ 13.3°

The other angle is approximately 76.7°.

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Always start by drawing a sketch

The angle opposite the 3-inch leg is sin^-1 ( 3/13 ) = you calculate ( answer A)
The other acute angle of the right triangle is = 90* - answer A =
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