How is this function even
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How is this function even

[From: ] [author: ] [Date: 12-04-09] [Hit: ]
1/(x² + 1), which makes an odd function.......
f(x) = x/(x^2+1)

my math book says this function is even, but by the test in which f(x) = f(-x) to be even, when its f(-x) isnt it -x/(x^2+1) therefore its not even, but odd right?

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This function is odd, it's definitely NOT even because you have an odd function, x, times an even function, 1/(x² + 1), which makes an odd function.
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