Calculus. Where does the series converge

Consider the series
∑ 11n(n+6)
(as n goes to infinity, n=1)
Determine where the series converges.

Please explain your steps. thank you.

I think you wrote this incorrectly. The terms are:

11x1x7=77
11x2x8=176
11x3x9 etc.

The series does not converge.

"Where it converges" implies there should be a variable term like x or t in the sum, but there isn't.

Every term in the series is bigger than eleven, and obviously 11+11+11+... diverges. None of those terms depends on z, so the answer is the same everywhere. The series converges on the empty set.

Possibly in Ignorant Land. What you wrote is nonsense.