Algebra inverse logarithms help
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Algebra inverse logarithms help

[From: ] [author: ] [Date: 12-03-16] [Hit: ]
......
how to find the invserse of

y=3logbase4(3x-2) thanks!

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From the power identity of logarithms, you can rewrite your problem as:

y = logbase4(3x-2)^3

So:

4^y = (3x-2)^3

Solve for x:

(4^y)^(1/3) = 3x - 2
3x = (4^y)^(1/3) + 2
x = ((4^y)^(1/3) + 2)/3

Your inverse is:
y = ((4^x)^(1/3) + 2)/3
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