If √3tanA=3sinA then find the value of Sin^2-Cos^2 = ?

Pls help me

If √3tanA=3sinA then √3sinA/cosA=3sinA and √3sinA-3sinAcosA=0
giving sinA(√3-3cosA)=0 so either sinA=0 or cosA=√3/3.
Assuming you want sin^2(A)-cos^2(A) then since sin^2(A)+cos^2(A)=1
sin^2(A)-cos^2(A) =2sin^2(A)-1 and when sinA=0 this =-1.
sin^2(A)-cos^2(A) =1-2cos^2(A) =1/3 when cosA=√3/3

If √3tanA=3sinA then find the value of Sin^2-Cos^2 = ? ?
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If √3tanA =3sinA then find the value of (sinA)^2 - (cosA)^2.

√3tanA =3sinA
√3(sinA / cosA) =3sinA
√3 / cosA = 3
or cosA = √3 / 3 = x / r :-)
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x^2 + y^2 = r^2 :-)
(√3)^2 + y^2 = 3^2 or y = +/- √6

sinA = +/- √6 / 3 = y / r :-)
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(sinA)^2 - (cosA)^2 = (√6 / 3)^2 - (√3 / 3)^2 = 3 / 9 = 1/3
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Hope this helps!