derivative of sin inverse x please?
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Its 1/(1-x^2)^1/2 i.e one by root of one Minus x square
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formula for derivative of sin^-1 is 1/sqrt (1-x^2)
or 1/ (1-x^2) ^ 1/2
or 1/ (1-x^2) ^ 1/2
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it's 1 / (1 - x)^1/2
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1/√(1 - x^2)
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y = arcsin(x)
y' = 1/√(1 - x^2)
y' = 1/√(1 - x^2)