Help! Exact Value of X-intercept and Y-intercept

Can someone help me how to do the Exact Value of X-intercept and Y-intercept in this equation.
y= -2(x+3)^2+4 ....

Step by step please... as you can see i hate math, and im not the only one;)
Thanks.

**y-intercept**

The y-intercept of a function is defined as the value of the function when x=0 (the value of y at which the graph of the function crosses the y axis). Simply apply x=0 to the function and then solve for y:

y(x) = -2(x+3)²+4

y(0) = -2(0+3)²+4 = -2(3²)+4 = -2(9)+4 = -18+4 = -14

Therefore, the y-intercept occurs when x=0 and y=14, the point (0,14) on a coordinate plane.


**x-intercept**

The x-intercept of a function is defined as the value of the function when y=0 (the value of x at which the graph of the function crosses the x axis). Apply y=0 to the function and solve for x:

y = -2(x+3)²+4

0 = -2(x+3)²+4

The best way to proceed from here would be to put this quadratic into standard form, ax²+bx+c=0.

0 = -2(x²+6x+9)+4 = -2x²-12x-14

This equation can be written simpler by dividing both sides by -2, yielding this:

0 = x²+6x+7

Now apply the quadratic formula.

x = (-6±√(6²-4(1)(7)))/(2(1))

x = (-6±√8)/2 = (-6±2√2)/2 = -3±√2

Therefore, the two x-intercepts are -3-√2 and -3+√2.

No problem! Helping others understand mathematics is something I love doing.

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-2(x^2+6x+9)+4
-2x^2 - 12x - 18 + 4
-2x^2 - 12x - 14

Now factor out the -2

x^2 - 6x - 7

For the x-intercept, substitute y = 0
0 = x^2 - 6x - 7
0 = (x - 7) (x +1)
x = 7 and x = -1

For the y-intercept, substitute x = 0
y = -2 (0^2) - 12(0) - 7 = -7

I hope this information was very helpful.