I am stuck on this problem and would like a step by step explanation of how to get the answer please. Thank you.
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∫ x⁻² + cos(5x) dx=
=∫ 1/x² dx+ ∫ cos(5x) dx=
=-1/x + ⅕∫ cos(5x) d(5x)=
=-1/x + ⅕sin(5x) +C
=∫ 1/x² dx+ ∫ cos(5x) dx=
=-1/x + ⅕∫ cos(5x) d(5x)=
=-1/x + ⅕sin(5x) +C
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I think
∫ (x^(-2) + cos 5x) dx
∫ x⁻² + cos(5x) dx
=∫ 1/x² dx+ ∫ cos(5x) dx=
=-1/x + ⅕∫ cos(5x) d(5x)=
=-1/x + ⅕sin(5x) +C
∫ (x^(-2) + cos 5x) dx
∫ x⁻² + cos(5x) dx
=∫ 1/x² dx+ ∫ cos(5x) dx=
=-1/x + ⅕∫ cos(5x) d(5x)=
=-1/x + ⅕sin(5x) +C
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x^(-2+1)/(-2+1) + (1/5)sin(5x)
i left the first bit unsimplified so you could visualize it better.
i left the first bit unsimplified so you could visualize it better.
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∫ (x^(-2) + cos 5x) dx = -1/x + 1/5 sin 5x + C
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why do i keep drooling milk?