If log 2 = .3010, log 3 = .4771, and log 7 = .8451, evaluate the following. -----> log square root of 294.

If i don't pass my math test tomorrow, i can't graduate high school.

You need to use properties of logs: log(a)+ log(b)= log(a*b) and log (a^b)= b* log(a)

First you need to express 294 in terms of the values that you were given, so try to factor it.

Since 294= 3* 98= 3*2*49= 3*2*7*7

Then log(294)^(1/2)= (1/2) log(294)

= (1/2)log( 3*2*7*7)

= (1/2) [ log(3)+ log(2)+ log(7)+ log(7)]

Now substitute the numbers you were given and simplify:

(1/2)[ .4771 + .3010+ .8451+ .8451]

Hoping this helps!