Factor to find value of X
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Factor to find value of X

[From: ] [author: ] [Date: 11-12-14] [Hit: ]
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Factor to find the values of X that satisfy the equation -2x^2=7x-15.

Can someone please help me with this/ explain it. >__< Pleaseeeeeeee

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Move the -2x^2 to the other side of the equation to get 0=2x^2+7x-15............

After that you can use the quadratic formula or simple factoring...

A=2
B=7
C=-15
What I mean by this is the actual equation looks like this: (A)x^2+(B)x-(C)
To factor this you need something that multiplies to -30 (A*C) and also that adds to 7.. (your B value)

You will get 10 and -3 (10*-3)=30 and (10-3)=7.


once you have these values you can put them in a punnet square.


your first value in the square is 2x^2, second is -3x and the third is 10x while the fourth is -15

A punnet square is hard to explain, If you don't know how to set it up google it and hopefully you will see what i mean. The box is divided into four parts and what I mean by the first box is the top right, the second is the top left and the third and fourth are the bottom boxes.


You should now have a square of numbers. Factor this: what multiplies to -15 and also -3? -3 does.. so that is a factor.. do the other 4 factors and put them across the top and side of your punnet square. You should have something that looks like this:


(2x-3)(x+5)=0


That is your factored equation.. to get the values of x, also known as the intercepts, solve the above equation algebraically.

So, x=-5 and 1.5

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You first subtract -2x^2 to get 2x^2+7x-15.
You then factor it to get (2x-3)(x+5)
Solve for x from there to get x=3/2 and -5.
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