Find the zeros of f(x) = x^2 + 4x - 5

The ^ means it is an exponent (2 is an exponent for x)

How do you solve this?Please show step by step.
Thank you <3

Well first of all you have to expand the brackets out and find 2 numbers which will add to make -5 and times to make 4, which are -1 and 5 as -1+5= 4 and -1x5=-5. so you get (x-1) (x+5). then all you do is the numbers you got is what the zeros are but with different symbols at the front so the answer is 0= +1 or 0= -5. btw both are the answer :) hope that made sense!

use the quadratic forumula
it is
(-b +- sqrt(b^2-4ac))/2a There are two solutions, so the +- means one of the solutions is +, one is using minus.
a typical quadratic equation is in the form ax^2+bx+c
in this case a is 1, b is 4, and c is -5
so plug in to get
(-4+-sqrt36)/2
which equals 1 and -5
this way is more straightforward but there are easier ways such as factoring, but they dont work with irrational roots and are hard to work with with fractinal answers.

The quickest way to do it is by factoring - if you're good enough at factoring to do it!
f(x) = (x+5)(x-1)
Clearly, f(x) = 0 when x=-5 or x=1. Those are your zeros.

If you don't feel up to factoring, then use the quadratic equation, with a=1, b=4, and c=-5. It should give you the same answer.

Hope that helps!

Delta = 4^2 - 4*1*(-5) = 36

x1 = (- 4 - sqrt(36))/2 = (- 4 - 6)/2 = -10/2 = -5

x2 = (-4 +sqrt(36))/2 =(- 4 + 6)/2 = 2/2 = 1

factor
(x + 5)(x -1)
the zeros are x = -5,1

at y=0,
0 = x^2 + 4x - 5
(x-1)(x+5) = 0
x = 1, -5