How do you Solve for this math problem

(a) Assuming each cube has numbers 1 through 6, the pair of cubes yield even numbers of 2, 4, 6, 8, 10, and 12 exactly once (e.g., 2 = 1 + 1, 4 = 2 + 2, etc.), a total = 6.

(b) Then the pair can yield odd numbers 3, 5, 7, 9, and 11 as follows:

3 = 1 + 2 = 2 + 1, total = 2

5 = 2 + 3 = 3 + 2 = 1 + 4 = 4 + 1, total = 4

7 = 1 + 6 = 6 + 1 = 2 + 5 = 5 + 2 = 3 + 4 = 4 + 3, total = 6

9 = 3 + 6 = 6 + 3 = 4 + 5 = 5 + 4, total = 4

11 = 5 + 6 = 6 + 5, total = 2

for a total = 2 + 4 + 6 + 4 + 2 = 18

(c) For the grand total number of possible outcomes (24 = 6 + 18) the number of

outcomes < 5 = 4, so the odds for < 5 are 4/24 = 1/6,

and for > 9 the outcomes are also = 4 yielding the

same odds for > 9 of 1/6.

actually you should know this whats less than 5 01234 and greater than 9 10 11 12 13 14 15 16 17 18 19 20 now the answer is add 9+5 and you'll get 14 thats the only way you can get an answer for this or ask a teacher duhhh your should rate mines as best answer for this because you probaly didn't get it

OK

For two number cubes the total number of all possible outcomes is 36 as follows:

Outcome - # of chances
2 ---- 1
3 ---- 2
4 ---- 3
5 ---- 4
6 ---- 5
7 ---- 6
8 ---- 5
9 ---- 4
10 --- 3
11 --- 2
12 --- 1

To get less than a 5 there are 6/36 or 1/6
To get greater than a 9 there are 6/36 or 1/6
To get either of these two would be 12/36 or 1/3

Hope that helps.