the region bounded by y = 1/2(x-2)^2 and y = 2 about the y-axis.
I get 64 pi/ 3 as the answer...and there's no way to verify this problem. Can some1 please try it?
I get 64 pi/ 3 as the answer...and there's no way to verify this problem. Can some1 please try it?
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Sorry it took me so long to get back to you; I used the shell method and did the integration:
(integral)(0 to 4)2pi*x(2 - (1/2)(x - 2)^2) dx and came up with 64pi/3 also. We must be right!
(integral)(0 to 4)2pi*x(2 - (1/2)(x - 2)^2) dx and came up with 64pi/3 also. We must be right!