How do you solve this..
m = nb + q (b)
I got the answer ---> m-q/ n = b..
Not sure if it's right though
m = nb + q (b)
I got the answer ---> m-q/ n = b..
Not sure if it's right though
-
nb + q = m
nb = m - q
b = (m - q)/ n
You are correct ( the other answers are miles out, there's no need to factor, they've mistaken the q(b) for qb, whereas it's only to show you which letter to put as the subject) but to be safe put brackets around the m - q so as not to be confused with m - q/n which is different from (m - q)/ n
nb = m - q
b = (m - q)/ n
You are correct ( the other answers are miles out, there's no need to factor, they've mistaken the q(b) for qb, whereas it's only to show you which letter to put as the subject) but to be safe put brackets around the m - q so as not to be confused with m - q/n which is different from (m - q)/ n
-
m = nb + qb
Factoring out b, we have
m = (n+q)b
Isolating b,
b = m/(n+q)
Factoring out b, we have
m = (n+q)b
Isolating b,
b = m/(n+q)
-
on the right hand side take b as a common factor:
m= b(n+q)
Then divide both sides by (n+q):
m/(n+q) = b
It's as simple as that :)
m= b(n+q)
Then divide both sides by (n+q):
m/(n+q) = b
It's as simple as that :)