Use Riemann sums and limits to compute the area bounded by
f(x)=6 x + 5
and the x axis between x=11 to x =10
Please help, thank you!
f(x)=6 x + 5
and the x axis between x=11 to x =10
Please help, thank you!
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dx = 1/n
x(i) = 10 + i/n
i = 0, n-->inf
area = sum [i = 0, n] f(x(i)) dx
= sum [i = 0, n->inf] [6(10 + i/n) + 5]/n
= 65 + 6(1/2)
= 68
x(i) = 10 + i/n
i = 0, n-->inf
area = sum [i = 0, n] f(x(i)) dx
= sum [i = 0, n->inf] [6(10 + i/n) + 5]/n
= 65 + 6(1/2)
= 68
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Thank you for picking my answer as the best answer. But your comment is bad. 68 is the right answer. If you don't believe, use integration to verify it.
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