can someone please show the steps to solve the following problem
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F(x,x) means y and x are equal. So substitute x for y.
F(x,x) = 2xx + 3x - 4x - 1 = 2x^2 - x - 1
You are supposed to find where 2x^2 - x - 1 = 0, which is a simple quadratic equation. Solve it with standard methods.
The discriminant b^2 - 4ac = 1^2 - 4*(-1)*2 = 9 is a perfect square, so it is going to have two rational solutions.
F(x,x) = 2xx + 3x - 4x - 1 = 2x^2 - x - 1
You are supposed to find where 2x^2 - x - 1 = 0, which is a simple quadratic equation. Solve it with standard methods.
The discriminant b^2 - 4ac = 1^2 - 4*(-1)*2 = 9 is a perfect square, so it is going to have two rational solutions.
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x=1