Graph the equation AND state the Domain & Range: y = |x+2| -1

Email me the answer on a graph, thanks:) alexiak@ymail.com

Since
|x+2| = (x+2) for x >= -2 and
|x+2| = -(x+2) for x<= -2,
thus draw 2 lines y1, y2 as
y1 = (x+2) - 1 or
y1 = x + 1 for x>= -2 (only take the portion for x>= -2), and
y2 = -(x+2) - 1 or
y2 = -x - 3 for x<= -2 (only take the portion for x<= -2)

Since there is no limit on x for the domain is all real numbers.
Since |x+2| >0 and has a minimum of 0, the range of y is >= -1.