Find the derivative of e^(2ln(x))

How would you find the derivative of e^2ln(x)?
I'm a little stuck..
Please show working/explain?

First, simplify e^[2ln(x)] by noting that:
2ln(x) = ln(x^2), by the laws of exponents.

So, we have:
e^[2ln(x)] = e^[ln(x^2)] = x^2.

So, the derivative of e^[2ln(x)] is just the derivative of x^2, which is 2x.

I hope this helps!