CALCULUS: Derivative of a log function, very confused

Find dy/dx of

yln(x) + y^2 = 4x

Answer choices:


1. (4 - y) / (lnx + 2y)

2. (4 + y) / (lnx + 2y)

3. (4x - y) / (xlnx + 2xy)

4. (4x + y) / (xlnx - 2xy)

5. (4 + xy) / (xlnx - 2y)

6. (4x - y) / (lnx - 2xy)

y ln(x) + y^2 = 4x

y/x + ln(x) y ' + 2y y ' = 4

=> y ' (ln x + 2y) = 4 - (y/x)

y ' = (4x - y)/(2xy + x ln x) --------option (3)

y'lnx+y/x+2yy'=4 , (xlnx+2xy)y'=4x-y , answer is 3