Evaluate the following integral by making the given substitution:
∫ ((dt) / ((1 - 6t)^4))
u= 1 - 6t
Any and all help is much appreciated! Thanks so much in advance!
∫ ((dt) / ((1 - 6t)^4))
u= 1 - 6t
Any and all help is much appreciated! Thanks so much in advance!
-
u = 1-6t
du = 6dt ; dt = 1/6du
∫ ((dt) / ((1 - 6t)^4)) = 1/6 ∫ 1/(u^4) du
1/6 * -(1/3)(1/u^3) + C
now just substitute u for 1-6t and simplify.
du = 6dt ; dt = 1/6du
∫ ((dt) / ((1 - 6t)^4)) = 1/6 ∫ 1/(u^4) du
1/6 * -(1/3)(1/u^3) + C
now just substitute u for 1-6t and simplify.