88! , tricky question ... Help
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88! , tricky question ... Help

[From: ] [author: ] [Date: 11-04-30] [Hit: ]
Then put a plus, divide the number BEFORE the plus by p, round down, and write that after the plus.Keep going until you get zeros.Lets look at a number like 24,......

In general, the number n! has [n/p] + [n/p^2] + [n/p^3] + ... factors of p in it, where [n] denotes the "round down" or "greatest integer" function. At some point, the denominator will be bigger than the numerator, so you'l lget a string of zeros at the end....or, in fancy math-speak, this series will converge.

As a practical matter, just divide n by p, and write down that number. Then put a plus, divide the number BEFORE the plus by p, round down, and write that after the plus. Keep going until you get zeros.

Let's look at a number like 24, and ensure that we counted correctly. 24 = 2 * 2 * 2 * 3, so it should contribute THREE powers of 2. And 24 appears on the first three lists, but not on the last 2.

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In base 10:
if a number ends with 1 zero, it is divisible by 10
if a number ends with 2 zeros, it is divisible by 100 (and 10 of course)
if a number ends with 3 zeros, it is divisible by 1000 (and 100 and 10)
etc....

The same applies to base 8:
If a number ends with 1 zero, it is divisible by 8 (88 is divisible by 8)
If a number ends with 2 zeros, it is divisible by 8^2 = 64

88 is NOT divisible by 64, but it is divisible by 8 ----> number will end with 1 zero

Note: 88₁₀ = 130₈

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88! = 88 factorial? If so, the answer is 22 I think. I'm not certain on this one but I divided 88 by 4 because the base 8 numbers in factorial add a 0 after every 4 factorials.



if not factorial. 88 base 10 is 130 base 8. So the answer would be 1.

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20

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Just 1, the answer is 130.

8 -> 10
16 -> 20

and so on until...

64 ->100

and then 72 -> 110

80 -> 120
88 -> 130
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