Profit/revenue question!help!!!:)
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Profit/revenue question!help!!!:)

[From: ] [author: ] [Date: 11-04-29] [Hit: ]
IDK the answer, but Capitals for the cup this year!!-Let x be the amount of 10 cent price increases.Then, profit(x) = p(x) = (275-25x)[2(1 + .......
A store owner can sell 275 key chains per day at a price of $2 each. The cost per key chain to the owner is $1.50. For each 10 cent increase in price, there is a decrease in sales of 25 key chains. What is her maximum daily profit

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Bro!! Update your baseball lineups you're losing!! IDK the answer, but Capitals for the cup this year!!

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Let x be the amount of 10 cent price increases.
Then, profit(x) = p(x) = (275-25x)[2(1 + .1x) - 1.5] = -5x^2 + 42.5x +137.5.

We take the derivative of p(x) to find the maximum value of x:
p'(x) = -10x + 42.5.

Set p'(x) = 0 and solve for x:
x = 4.25.

So, the maximum daily profit is p(4.25) = $677.34.
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