Please help: At a play 903 tickets were sold. The total receipts for the performance was $6,751.......

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Please help: At a play 903 tickets were sold. The total receipts for the performance was $6,751.......

[From: ] [author: ] [Date: 11-04-29] [Hit: ]

......

6751=7c+9a+214*5

so 7c+9a=6751-1070=5681
and a+c=689

multiply the second equation by 7 we get:

7a+7c=4823

so 7c+9a-7a-7c=2a=5681-4823=858
Hence a=858/2=429
so c=689-429=260

Hope this helps.

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7C + 9A + 5S= 6751
C + A + S = 903
C + A - 2S = 261

[7 9 5 | 6751]
[1 1 1 | 903]
[1 1 -2 | 261]

Row 3 - Row 2 = Row 3*

[7 9 5 | 6751]
[1 1 1 | 903]
[0 0 -3 | -642]

7(Row 2) - Row 1 = Row 2*

[7 9 5 | 6751]
[0 -2 2 | -430]
[0 0 -3 | -642]

-3S = -642
S = 214

-2A + 2(214) = -430
-2A + 428 = -430
-2A = -858
A = 429

7C + 9(429) + 5(214) = 6751
7C + 3861 + 1070 = 6751
7C + 4931 = 6751
7C = 1820
C = 260

So 429 adult tickets, 260 child tickets, and 214 senior tickets.

-

x+y+z=903
7x+9y+5z=6751
x+y=2z+261

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