How to evaluate the function at the values -3,9, and a

f(t)=t/t+1
please simplify
f(-3)=

f(9)=

f(a)=

f(-3) = -3/(-3 + 1) = -3/-2 = 3/2

f(9) = 9/(9 + 1) = 9/10

f(a) = a/(a + 1)

:)>

Simply substitute each given t value for the function! Therefore, we have:

f(-3) = -3/(-3 + 1)
= -3/-2
= 3/2

f(9) = 9/(9 + 1)
= 9/10

f(a) = a/(a + 1)

I hope this helps!

f(t)=t/(t+1)

f(-3)=(-3)/(-3+1)
f(-3)=(-3)/(-2)
f(-3)=(3/2)

f(9)=(9)/(9+1)
f(9)=(9)/(10)
f(9)=9/10

f(a)=a/(a+1)

f(-3) = -3 / -3 +1 = -3 / -2 = 1/5

f(9) = 9 / 9 + 1 = 9/10

f(a) = a/a+1