Find the equation of a parabola that passes through the points (-2,-2), (2,2), and (6,10).
Can someone with an aptitude for this please work this out and explain how to go about this? I believe there's a system that must be set up and solved for, and perhaps matrices should be involved. This seems to have stumped me! Thanks!
Can someone with an aptitude for this please work this out and explain how to go about this? I believe there's a system that must be set up and solved for, and perhaps matrices should be involved. This seems to have stumped me! Thanks!
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y = ax² + bx + c
-2 = y(-2) = 4a - 2b + c
2 = y(2) = 4a + 2b + c
10 = y(6) = 36a + 6b + c
Three equations, three unknowns.
-2 = y(-2) = 4a - 2b + c
2 = y(2) = 4a + 2b + c
10 = y(6) = 36a + 6b + c
Three equations, three unknowns.