assume that a normal distribution of data has a mean of 10 and a standard deviation of 2. use the 68-95-99.7 rule to find the percentage of values that lie above 12.
I really don't understand. I know I take the absolute value of the difference between 12-10 and then I get two. then I divide 2/2 and get 1. after that, I don't know what to do. If someone could explain this to me I'd really appreciate it!
I really don't understand. I know I take the absolute value of the difference between 12-10 and then I get two. then I divide 2/2 and get 1. after that, I don't know what to do. If someone could explain this to me I'd really appreciate it!
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Normal distributions are a special case in statistics.
68% of all numbers in a normal distribution are within one standard deviation of the mean.
95% of all numbers in a normal distribution are within two standard deviations of the mean.
99.7% of all numbers in a normal distribution are within three standard deviations of the mean.
Here, 68% are between 8 and 12, 95% are between 6 and 14, and 99.7% are between 4 and 16.
Normal distributions are evenly spread. This set has 34% of all values between 10 and 12, and half (50%) are less than 10. Therefore 34%+50%=84% are less than 12, so 100%-84%=16% are above 12.
68% of all numbers in a normal distribution are within one standard deviation of the mean.
95% of all numbers in a normal distribution are within two standard deviations of the mean.
99.7% of all numbers in a normal distribution are within three standard deviations of the mean.
Here, 68% are between 8 and 12, 95% are between 6 and 14, and 99.7% are between 4 and 16.
Normal distributions are evenly spread. This set has 34% of all values between 10 and 12, and half (50%) are less than 10. Therefore 34%+50%=84% are less than 12, so 100%-84%=16% are above 12.