1. Two brothers depart from home and travel in opposite directions on an expressway . one travels 8km/hr faster than the other. If the brothers are 380 km apart after 2.5 hrs, how fast is each traveling.
#2. x-y= -1
3x-2y= 2
Help me please, 10 points for quickest answer.
#2. x-y= -1
3x-2y= 2
Help me please, 10 points for quickest answer.
-
Let the respective distance covered be x and y.
=>X=y+8km/hr
=>after 2.5hrs=380km.
=>average distance=380km/2.5hrs=152km/hr
=>(152/2)km/hr=76km/hr
=>y=(76-8)km/hr=68km/hr
#2
using elimination method.
Multiply equation(1) and (2) by 3 and 1,respectively.
x-y=-1*3
3x-2y=2*1
gives equation 3 and 4
=>3x-2y=-3.........equtn(3)
=>3x-3y=2.........eqution(4)
subtract equtn 4 from 3
we have
=>-3y+2y=-3-2
=>-y=-5
=>y=5
to get the value of x,subst for y with "5" in eqution (1)
=>x-y=-1
=>x-(5)=-1
=>x=-1+5
=>x=4
=>X=y+8km/hr
=>after 2.5hrs=380km.
=>average distance=380km/2.5hrs=152km/hr
=>(152/2)km/hr=76km/hr
=>y=(76-8)km/hr=68km/hr
#2
using elimination method.
Multiply equation(1) and (2) by 3 and 1,respectively.
x-y=-1*3
3x-2y=2*1
gives equation 3 and 4
=>3x-2y=-3.........equtn(3)
=>3x-3y=2.........eqution(4)
subtract equtn 4 from 3
we have
=>-3y+2y=-3-2
=>-y=-5
=>y=5
to get the value of x,subst for y with "5" in eqution (1)
=>x-y=-1
=>x-(5)=-1
=>x=-1+5
=>x=4
-
Their combined distance is 380 km in 2.5 hours
=> their combined speed is 380 km / 2.5 hours = 152 km/h
So if we call their speeds x and y:
x + y = 152
x - y = 8
=> y = x - 8
So substituting into the first equation:
x + (x-8) = 152
etc
=> their combined speed is 380 km / 2.5 hours = 152 km/h
So if we call their speeds x and y:
x + y = 152
x - y = 8
=> y = x - 8
So substituting into the first equation:
x + (x-8) = 152
etc